15x^2-7x^2=1

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Solution for 15x^2-7x^2=1 equation:



15x^2-7x^2=1
We move all terms to the left:
15x^2-7x^2-(1)=0
We add all the numbers together, and all the variables
8x^2-1=0
a = 8; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·8·(-1)
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{2}}{2*8}=\frac{0-4\sqrt{2}}{16} =-\frac{4\sqrt{2}}{16} =-\frac{\sqrt{2}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{2}}{2*8}=\frac{0+4\sqrt{2}}{16} =\frac{4\sqrt{2}}{16} =\frac{\sqrt{2}}{4} $

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